Log X 2

Log X 2. Solve for x log of x=2 log(x) = 2 log ( x) = 2 Rewrite log(x) = 2 log ( x) = 2 in exponential form using the definition of a logarithm If x x and b b are positive real numbers and b b ≠ ≠ 1 1 then logb (x) = y log b ( x) = y is equivalent to by = x b y = x 102 = x 10 2 = x Solve for x x.

Here log ⁡ x 2 by definition is that number which is when raised to e [or e (⋯)] gives x 2 as output And when we give e the exact same power it gives x 2 as output (as expected) Therefore we can say that e log ⁡ x 2 = x 2 by the definition of logarithms itself.

What is (log x)^2? Quora

log b x = y with b being the base x being a real number and y being an exponent For example 2 3 = 8 ⇒ log 2 8 = 3 (the logarithm of 8 to base 2 is equal to 3 because 2 3 = 8) Similarly log 2 64 = 6 because 2 6 = 64 Therefore it is obvious that logarithm operation is an inverse one to exponentiation.

SOLUTION: solve: log x^2= (log x)^2 Algebra

It follows that log^2(a^{f(x)})=f(x)log(a)f(x)log(a)=f^2(x)log^2(a) Therefore it is the second one More Items Share Copy Copied to clipboard Examples Quadratic.

Solve log(x^23x) Microsoft Math Solver

Since there is no base noted in subscript to the right of the log this logarithm is in base 10 We can convert directly to exponential form logx = 2 x = 10^2 x = 1/(10^2) x = 1/100 The answer is x = 1/100 Practice exercises Solve the following logarithmic equations Round solutions to the nearest hundredth whenever necessary a) log(x + 1) = 1 b) log_7(x 2) = 2 Good luck!.